91 f2 f3 93 -etc- Example: TABRND1 32.5 .01057 2.6 .01362 ENDT 3)
Field
Contents
TID XAXES YAXIS
Tabla identification number. (IrrlegeruO)
Specifies a linear or togarithmic interpolation for Itie x-axis. (Character: \"LINEAR\" or
1_0孑;Default=HLlNEAR\")
Specifies a linear or logafithmic interpolaiion far liie y-axis. (Character: LINEAR'
or
\"LOG: Default^TlNEAR\")
fi
Frequency value in cycles per unit time. (Realwfl.O) Power spectral density. {Real)
9 = 9T(f)
Extrapolated
11.5.3随机响应输入要求
1)执行控制
SOL (required)
Structured Solution Seq uences Direct
108 111 Modal 2 )情况控制
RANDOM (selects Bulk Data RANDPS, RANDT entries and en-tries for frequency response, and must be above the subcases)
3)模型数据
RANDPS
RANDT1
(PSD specification)
(autocorrelation time lag entries for frequency response)
11.5.4 随机响应例子
1)例1:单输入随机响应分析
(1)问题描述:
(a)矩形板如图;(b)基座运动(z方向)功率谱(PSD)表中给出;(c)整个频率范围 的常临界阻尼
比为0.03 ; (d)用log-log输入PSD;(e)使用模态求解法
0 55
Autospectra of the Base Excitation Frequency (Hz) 20 30 100 500 G2/HZ 0.1 1 1 0.1 0.1 1000
(2) 使用具有大质量的模态法(在边界处用 REB2单元)确定
a) 9999点处的位移和加速度功率谱 (PSD) b) 确定结点33和55的位移功率谱(PSD)
(3)
输入文件
ID SEMINAR, PROB10 SOL 111 TIME 30 CEND
TITLE= RANDOM ANALYSIS - BASE EXCITATION
SUBTITLE= USING THE MODAL METHOD WITH LANCZOS ECHO= UNSORTED SPC= 101
SET 11仁 33, 55, 9999
ACCELERATION(SORT2, PHASE)= 111 METHOD= 100 FREQUENCY=100 SDAMPING= 100 RANDOM= 100 DLOAD=100 $
OUTPUT(XYPLOT) XTGRID= YES YTGRID= YES XBGRID= YES YBGRID= YES YTLOG= YES
XTITLE= FREQUENCY
YTTITLE= ACCEL RESPONSE BASE, MAGNITUDE YBTITLE= ACCEL RESPONSE AT BASE, PHASE XYPLOT ACCEL RESPONSE / 9999 (T3RM, T3IP)
YTTITLE= ACCEL RESPONSE AT TIP CENTER, MAGNITUDE
YBTITLE= ACCEL RESPONSE AT TIP CENTER, PHASE XYPLOT ACCEL RESPONSE / 33 (T3RM, T3IP)
YTTITLE= ACCEL RESPONSE AT OPPOSITE CORNER, MAGNITUDE
YBTITLE= ACCEL RESPONSE AT OPPOSETE CORNER, PHASE XYPLOT ACCEL RESPONSE / 55 (T3RM, T3IP) $
$ PLOT OUTPUT IS ONLY MEANS OF VIEWING PSD DATA $
XGRID= YES YGRID= YES XLOG= YES YLOG= YES
YTITLE= ACCEL P S D AT LOADED CORNER XYPLOT ACCEL PSDF / 9999(T3) YTITLE= ACCEL P S D AT TIP CENTER XYPLOT ACCEL PSDF / 33(T3)
YTITLE= ACCEL P S D AT OPPOSITE CORNER XYPLOT ACCEL PSDF / 55(T3) $
BEGIN BULK
PARAM,COUPMASS,1 PARAM,WTMASS,0.00259 $
INCLUDE 'plate.bdf ' $
GRID, 9999, , 0., 0., 0. $
RBE2, 101, 9999, 12345, 1, 12, 23, 34, 45 $
SPC1, 101, 12456, 9999 $
CONM2, 6000, 9999, , 1.0E8 $
$MAT1, 1, .1, , .1, .286 $
$ EIGENVALUE EXTRACTION PARAMETERS $
EIGRL, 100 , , 2000. $
$ SPECIFY MODAL DAMPING $
TABDMP1, 100, CRIT, +, 0., .03, 10., .03, ENDT $
$ POINT LOADING AT TIP CENTER $
RLOAD2, 100, 600, , , 310 $
TABLED1,310,
+, 10., 1., 1000., 1., END $
DAREA, 600, 9999, 3, 1.E8 $
$ SPECIFY FREQUENCY STEPS $
FREQ,100,30. FREQ1,100,20.,20.,50 FREQ4,100,20.,1000.,.03,5 $
$ SPECIFY SPECTRAL DENSITY $
RANDPS, 100, 1, 1, 1., 0., 111 $
TABRND1, 111 ,L OG, LOG +, 20., 0.1,30., 1., 100., 1., 500., .1, +, 1000., .1, ENDT $
ENDDATA
(4)部分结果
T
基座的加速度PSD(大小、相位)与频率关系
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结点55的加速度PSD(大小、相位)与频率关系
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结点33的加速度PSD(大小、相位)与频率关系
例2:多输入随机响应分析 问题:
Using the modal method, determine the displacement response spec-trum of the tip center point due to the input spectrum of the pressure and point loads listed below. U吕e the complex matrix representation (SAB) for the cross spectrurn.
Autospectra of Pressure Load Frequency (Hz) 20 30 100 500 Auto Spectra of Corner Load Frequency (Hz) 20 30 500 1000 psi/Hz 0J 1 1 0.1 0.1 Ib/Hz 0.5 2.5 2.5 0 1000 Cro^s・SpRdnjm of Pressure and Corner Load$ Real/lmaginary Frequency (Hz) 20 100 500 1000 输入文件 ID SEMINAR, PROB11 SOL 111 TIME 30 CEND
TITLE= FREQUENCY RESPONSE WITH PRESSURE AND POINT LOADS SUBTITLE= USING THE MODAL METHOD WITH LANCZOS ECHO= UNSORTED SPC= 1
SET 111= 11, 33, 55
DISPLACEMENT(PLOT, PHASE)= 111 METHOD= 100 FREQUENCY=100 SDAMPING= 100 RANDOM= 100
SUBCASE 1
Real Part -4.099619 -0.498097 0.070711 0 Imaginary Part 0.007816 0.043579 -0.070711 0 LABEL= PRESSURE LOAD DLOAD= 100 LOADSET= 100 SUBCASE 2
LABEL CORNER LOAD DLOAD= 200 LOADSET= 100 $
OUTPUT (XYPLOT) $
XTGRID= YES YTGRID= YES XBGRID= YES YBGRID= YES YTLOG= YES YBLOG= NO
XTITLE= FREQUENCY (HZ)
YTTITLE= DISPLACEMENT RESPONSE AT LOADED CORNER, MAGNITUDE YBTITLE= DISPLACEMENT RESPONSE AT LOADED CORNER, PHASE XYPLOT DISP RESPONSE / 11 (T3RM, T3IP)
YTTITLE= DISPLACEMENT RESPONSE AT TIP CENTER, MAGNITUDE YBTITLE= DISPLACEMENT RESPONSE AT TIP CENTER, PHASE XYPLOT DISP RESPONSE / 33 (T3RM, T3IP)
YTTITLE= DISPLACEMENT RESPONSE AT OPPOSITE CORNER, MAGNITUDE YBTITLE= DISPLACEMENT RESPONSE AT OPPOSITE CORNER, PHASE XYPLOT DISP RESPONSE / 55 (T3RM, T3IP) $
$ PLOT OUTPUT IS ONLY MEANS OF VIEWING PSD DATA $
XGRID= YES YGRID= YES XLOG= YES YLOG= YES
YTITLE= DISP P S D AT LOADED CORNER XYPLOT DISP PSDF / 11(T3) YTITLE= DISP P S D AT TIP CENTER XYPLOT DISP PSDF / 33(T3)
YTITLE= DISP P S D AT OPPOSITE CORNER XYPLOT DISP PSDF / 55(T3) $
BEGIN BULK
PARAM,COUPMASS,1 PARAM,WTMASS,0.00259 $
$ MODEL DESCRIBED IN NORMAL MODES EXAMPLE $ INCLUDE 'plate.bdf ' $
$ EIGENVALUE EXTRACTION PARAMETERS $
EIGRL, 100, 10., 2000. $
$ SPECIFY MODAL DAMPING $
TABDMP1, 100, CRIT, +, 0., .03, 10., .03, ENDT $
$ FIRST LOADING $
RLOAD2, 100, 300, , , 310 $
TABLED1, 310,
+, 10., 1., 1000., 1., ENDT
$
$ UNIT PRESSURE LOAD TO PLATE $
LSEQ, 100, 300, 400 $
PLOAD2, 400, 1., 1, THRU, 40 $
$ SECOND LOADING $
RLOAD2, 200, 600, , , 310 $
$ POINT LOAD AT TIP CENTER $
DAREA, 600, 11, 3, 1. $
$ SPECIFY FREQUENCY STEPS $
FREQ1, 100, 20., 20., 49 $
$ SPECIFY SPECTRAL DENSITY $
RANDPS, 100, 1, 1, 1., 0., 100 RANDPS, 100, 2, 2, 1., 0., 200 RANDPS, 100, 1, 2, 1., 0., 300 RANDPS, 100, 1, 2, 0., 1., 400 $ TABRND1, 100,
+, 20., 0.1, 30., 1., 100., 1., 500., .1, +, 1000., .1, ENDT $
TABRND1, 200,
+, 20., 0.5, 30., 2.5, 500., 2.5, 1000., 0., +, ENDT $
TABRND1, 300,
+, 20., -.099619, 100., -.498097, 500., .070711, 1000., 0., +, ENDT $
TABRND1, 400,
+, 20., .0078158, 100., .0435791, 500., -.70711, 1000., 0., +, ENDT $
ENDDATA